Math, asked by wansengmarak8pdhzmc, 11 months ago

If a-b=3 and a^2+b^2=29,find the value of ab

Answers

Answered by mannvora74pddroc
8
here's the solution.
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Answered by Anonymous
4
Hey !!! ^_^

Here is your answer

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⏩GIVEN

a - b = 3

 {a}^{2}  +  {b}^{2}  = 29
ab = ??


a³ - b³ = (a - b)(a² + b² + ab)


(a - b)(a² + b² + ab) = 0

3( 29 + ab) = 0

87 + 3ab = 0

3ab = - 87

ab = (-29)



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wansengmarak8pdhzmc: Ok
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