If a-b=3 and a^2+b^2=29,find the value of ab
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here's the solution.
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Hey !!! ^_^
Here is your answer
⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️
⏩GIVEN
a - b = 3
ab = ??
a³ - b³ = (a - b)(a² + b² + ab)
(a - b)(a² + b² + ab) = 0
3( 29 + ab) = 0
87 + 3ab = 0
3ab = - 87
ab = (-29)
____________________
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Here is your answer
⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️
⏩GIVEN
a - b = 3
ab = ??
a³ - b³ = (a - b)(a² + b² + ab)
(a - b)(a² + b² + ab) = 0
3( 29 + ab) = 0
87 + 3ab = 0
3ab = - 87
ab = (-29)
____________________
I HOPE IT WILL HELP YOU ☺️✌️
Thank you ✌️
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