Question

if a+b=√3 and a-b 1÷√3 then find value of a and b
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Answer 1

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a + b = √3___________(1)

a - b = 1/√3________________(2)

Add (1) and (2)

a + b + a - b = √3 + 1/√3

2a = 3 + 1/√3

2a = 4/√3

a = 4/√3 × 2

a = 2/√3

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Put Value of a in (1)

2/√3 + b = √3

b = √3 - 2/√3

b = √3-2/√3

Answer 2

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$\star \: \: \: \sf a + b = \sqrt{3} \: - - - - \: (i) \\ \\ \sf \star \: \: \: a - b = \frac{1}{ \sqrt{3} } \: - - - - \: (ii)$

By elimination method , Add equation (i) and (ii)

$\implies \sf a + b + (a - b)= \sqrt{3} + \frac{1}{ \sqrt{3} } \\ \\ \implies \sf 2a = \frac{3 + 1}{ \sqrt{3} } \\ \\ \implies \sf a = \frac{2}{ \sqrt{3} }$

Put the value of a = 2/√3 in eq (i)

$\implies \sf \frac{2}{ \sqrt{3} } + b = \sqrt{3} \\ \\ \implies \sf b = \sqrt{3} - \frac{2}{ \sqrt{3} } \\ \\ \implies \sf b = \frac{3 - 1}{ \sqrt{3} } \\ \\ \implies \sf b = \frac{1}{ \sqrt{3} }$

$\therefore$The required values of a and b are 2/√3 and 1/√3