if a-b=3 and a+b=5 then find ab and a^2+b^2
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Step-by-step explanation:
a-b=3
a=3+b. -1
a+b=5
sub 1 in eq
3+b+b=5
3+2b=5
2b=5-3
b=1. -2
sub 2 in 1
a=3+1
a=4
therefore ab =4×1=4
a^2+b^2= 4^2+1^2
= 16+1
=17
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