Question

If a - b = 3 and a2 + b2 = 29, find the value of ab.

Answer 1

Hi,

According to the problem given,

a - b = 3 ---( 1 )

a² + b² = 29----( 2 )

We know that the algebraic identity,

( a - b )² = a² + b² - 2ab

3² = 29 - 2 ab

[ From ( 1 ) and ( 2 ) ]

9 = 29 - 2ab

2ab = 29 - 9

2ab = 20

ab = 20/2

ab = 10

I hope this helps you.

:)

Answer 2

Answer:

value of ab is 10

Step-by-step explanation:

Given $a - b = 3$ and $a^{2} +b^{2} = 29$

Substituting these in the algebraic identity,

                 $(a-b)^{2}= a^{2} +b^{2}-2ab$

                  $\implies 3^{2}= 29 -2ab$

                  $\implies 2ab=29-9=20$

                  $\implies ab=\frac{20}{2} =10$