Question

if a-b=3 and ab=10then find the value of a2+b2-2ab​

Answer 1

Step-by-step explanation:

a-b =3

a^2+b^2 =29

(a-b)^2 =a^2+B^2–2 ab

(3)^2 =29–2 ab

9 =29–2 a b

9–29 =-2 a b

-20 =-2 a b

2 a b =20

a b =20/2 =10

( substitute the value of 2 ab then 3^2 =29–10*2 =9)

Answer 2

Answer:

(a-b)^2=a^2+b^2-2ab

(3)^2=a^2+b^2-2(10)

9=a^2+b^2-20

a^2+b^2=20+9=29

a^2+b^2+2ab=29-2(10)=29-20=9