If a+b=3 and ab =2 find the value of a^3+b^3
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a + b = 3
Cube on both sides-
Using ( x + y )^3 = x^3 + y^3 + 3xy( x + y )
= > ( a + b )^3 = 3^3
= > a^3 + b^3 + 3ab( a + b ) = 27
ab = 2 and a + b = 3
= > a^3 + b^3 + 3(2)(3) = 27
= > a^3 + b^3 + 18 = 27
= > a^3 + b^3 = 27 - 18
= > a^3 + b^3 = 9
Hence a^3 + b^3 = 9
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