Question

if a+b = 3 and ab = 2 fit the value of
a²+b²
​

Answer 1

Answer:

Step-by-step explanation:

a + b = 3 , & ab = 2

NOW,

we know that:-

(a + b)² = a² + b² + 2ab

Now,

(a + b) = 3

[ On SQUARING both side]

(a + b )² = 3²

a² + b² + 2ab = 9

=> a² + b² + 2×2 = 9

=> a² + b² = 9 - 4

=> (a² + b²) = 5

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Answer 2

${\huge{\underline{\underline{\mathfrak{\red{Answer:-}}}}}}$

${\huge{\underline{\underline{\bold{\red{Given:-}}}}}}$

$a + b = 3\: and\: ab = 2$

${\huge{\underline{\small{\bold{\purple{Now,}}}}}}$

${\huge{\underline{\small{\bold{\green{we\:know\:that:-}}}}}}$

$(a + b)^2 = a^2+ b^2+ 2ab$

${\huge{\underline{\small{\bold{\blue{Now,}}}}}}$

$(a + b) = 3$

$[ On\: SQUARING\: both\: side]$

$(a + b )^2 = 3^2$

$a^2 + b^2+ 2ab = 9$

$=> a^2+ b^2+ 2×2 = 9$

$=> a^2 + b^2 = 9 - 4$

$=> (a^2 + b^2) = 5$