if a-b=3 and ab=4,find a³-b²
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1
Answer:
15
Step-by-step explanation:
We have two equations,
a-b =3 --(1)
ab=4 --(2)
now solve for a and b,
from eq. (1) we get: a=3+b --(3)
from eq. (2) we get a=4/b --(4)
Equate equation a from (3) and (4),
we get: 3+b = 4/b
=> 3b + b^2 =4
=> b^2 +3b -4 = 0
Solving the above quadratic equation we find the roots of b.. ie, b=1 and-4.
Since -4 is negative lets assume b =1, substituting the value of b in equation (2) we get the value of a.
Therefore, a=4 and b=1.
Now we know the values a and b, substitute in a^3-b^2
ie, (4)^3 - (1)^2
=> 16 - 1
=> 15
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