If a-b=3 and ab =40 ,find a2 + b2
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0 is the ans
Step-by-step explanation:
a-b=3 ab=40
a=3+b b=40/a
a=3+40/a b=40/3+b
a=3a+40÷a b(3+b)=40
a²-3a-40 3b+b²=40
a²-(8a-5a)-40 b²+3b-40
a²-8a+5a-40 b²+8b-5b-40
a(a-8)+5(a-8) b(b+8)-5(b+8)
(a+5)(a-8) (b-5)(b+8)
a=-5 a=8 b=5 b=-8
a2+b2= -5(2)+5(2)
= 0
a2+b2= 8(2)-8(2)
= 0
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