Math, asked by rajkarannirmal534, 3 months ago

If a - b = 3 and (aXa) + (bXb) = 29 find the
value of ab.​

Answers

Answered by reeyakundu011
0

Answer:

10

Step-by-step explanation:

(a-b)^2=3^2

a^2-2ab+b^2=9

(a^2+b^2)-2ab=9

29-2ab=9[a^2+b^2=29]

-2ab=9-29

-2ab=-20

ab=-20/-2

Hence, ab=10

Similar questions