If a-b=3 and b-c=5 then find a^2-b^2-c^2-ab-bc-ca
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49 is the answer !!!!!!!!!!!!!
vishnukrishna:
Can u explain?
a-b=3----(1)
b-c=5-----(2)
(1)+(2)
a-b+b-c=8
a-c=8
(a-b)^2=a^2+b^2-2ab
9=a^2+b^2-2ab-----(A)
(b-c)^2=b^2+c^2-2bc
25=b^2+c^2-2bc------(B)
(a-c)^2=a^2+c^2-2ac
64=a^2+c^2-2ac-------(C)
(A)+(B)+(C)
9+25+64=2(a^2+b^2+c^2-ab-bc-ca)
98=2(a^2+b^2+c^2-ab-bc-ca)
a^2+b^2+c^2-ab-bc-ca=49
b-c=5-----(2)
(1)+(2)
a-b+b-c=8
a-c=8
(a-b)^2=a^2+b^2-2ab
9=a^2+b^2-2ab-----(A)
(b-c)^2=b^2+c^2-2bc
25=b^2+c^2-2bc------(B)
(a-c)^2=a^2+c^2-2ac
64=a^2+c^2-2ac-------(C)
(A)+(B)+(C)
9+25+64=2(a^2+b^2+c^2-ab-bc-ca)
98=2(a^2+b^2+c^2-ab-bc-ca)
a^2+b^2+c^2-ab-bc-ca=49
Answered by
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Heya!
49 is the answer for your question
49 is the answer for your question
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