Question

if a-b=3 and b-c=5,then the value of a^2+b^2+c^2-ab-bc-ca will be??

Answer 1

hello users ......

we have given that 
a - b = 3 ...........(1)  , b - c = 5 .................(2)

we have to find 
 a² + b² + c² -ab - bc - ca = ?

solution:-
now adding  (1) and (2) ,we get
a - c = 3 +5 = 8 ...........(3)

now squaring and adding (1) ,(2) and (3)
we get 
 (a - b)² + ( b - c)² + (a - c)² = 3²  + 5²  + 8² 
=  (a² + b² - 2ab ) +(b² + c² - 2bc) + ( a² + c² - 2ac) = 9 + 25 + 64
= 2a² +2b² +2c² -2ab - 2bc - 2ac = 98
= 2(a² +b² +c² -ab - bc - ac) = 2 × 49

=> (a² +b² +c² -ab - bc - ac) = 49 answer 


 ✪✪ hope it helps ✪✪