if (a+b)=√3 and tan(a-b)=1/√3;0° <a+b<90°; a>b find and b
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Answered by
5
Hope this helps!
A = 45°
B= 15°
A = 45°
B= 15°
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Answered by
2
Given ,
tan(A+B) = √3 = 60°
So , A+B = 60°. (1)
tan(A-B) = 1/√3 = 30°
So, (A-B) = 30°. (2)
Using 1 and 2 ,
A=45° , B=15°
tan(A+B) = √3 = 60°
So , A+B = 60°. (1)
tan(A-B) = 1/√3 = 30°
So, (A-B) = 30°. (2)
Using 1 and 2 ,
A=45° , B=15°
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