Question

if (a-b) =3,(b-c) = 5,(c-a)=1
then find the value of a^3+b^3+c^3-ab-bc-ca/a+b+c​

Answer 1

Answer:

a^3+b^3+c^3 – 3abc = (a+b+c) ( a^2+b^2+c^2 – ab – bc – ca )

=> (a^3+b^3+c^3-3abc)÷a+b+c = (2/2)( a^2+b^2+c^2-2ab-2bc-2ac)

= (1/2){ (a – b)^2 + (b – c )^2 + (c – a)^2 }

= (1/2) { 9 + 25 + 1 } = 35/2 .

Step-by-step explanation:

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