Question

If a/b= 4/5 and b/c= 15/16 then c^2+a^2/c^2-a^2 = K. Find smallest integer value of 7K.

please tell me the answer

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Answer 1

Answer:

a/c=3/4

a=3c/4

put value of a

hence

c^2 +9/16-9c^2/16

taking LCM

(16c^2+9-9c^2) /16

7c^2+9=16k

fork to be mini. c=-1

or c=1

hence k=1

then

7k =7

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