Question

if a/b = 4/5 and b/c = 15/16, then c^2-a^2/c^2+a2 is equal to​

Answer 1

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Answer 2

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Step-by-step explanation:

$\frac{a}{b } = \frac{4}{5 } - - - - -(1) \\ \frac{b}{c} = \frac{15}{16} = > b = \frac{15c}{16 } \\ put \: in(1)we \: get \: a = \frac{4 \times 15c}{5 \times 16} \\ = > a = \frac{3c}{4}$

$= > {a}^{2} = \frac{9 {c}^{2} }{16} \\ substituting \: in \: given \: equation \\ \: we \: get \frac{ {c}^{2} - {a}^{2} }{ {c}^{2} + {a}^{2} } = \frac{7 {c}^{2} }{25 {c}^{2} } = \frac{7}{25}$