If A: B = 4: 6 and B: C = 3: 4 then by what percentage is C more than A?
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Answer:
0% will C more than A because A:C=4:4
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A : B = 4 : 6
A/B = 4/6 ... (i)
B : C = 3 : 4
B/C = 3/4 ... (ii)
multiplying (i) and (ii), we get
(A/B)(B/C) = (4/6)(3/4)
A/C = 1/2
C = 2A
C = A + A
C = A + 100% of A
... (100% of A = (100/100) x A = A)
Hence, C is 100% more than A
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