If a+b =4, a^2+ b^2=16
Find a-b
Answers
Answered by
1
Answer:
a-b = ± 4
a and b are 4 & 0 respectively or vice versa
Step-by-step explanation:
a + b = 4
squaring both sides
(a+b)² = 4²
a² + b² + 2ab = 16
a² + b² = 16 given
16 + 2ab = 16
2ab = 0
(a-b)² = a² + b² - 2ab
(a-b)² = 16 - 2ab
(a-b)² = 16 - 0
(a-b)² = 16
a-b = ±4
case 1
a -b = 4
a + b = 4
2a = 8 => a = 4
b = 0
case 2
a-b = -4
a + b = 4
2a = 0 => a = 0
b = 4
Similar questions