Question

if (a - b) = 4, a2 + b2 = 40, then find a3-b3​

Answer 1

Step-by-step explanation:

$here {(a - b)}^{2} = {a}^{2} + 2ab + {b}^{2} \\ {4}^{2} = 40 + 2ab \\ 16 = 40 + 2ab \\ 8 = 20 + ab \\ ab = - 12 \\ {a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} ) \\ 4(40 - 12) \\ 4 \times 28 \\ 112$

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