if a-b=4;ab=45. find a³-b³
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Answer:
a^3-b^3=(a-b)(a^2+ab+b^2)
a^3-b^3=(a-b) (a^2-2ab+b^2+2ab+ab)
a^3 −b^3 =(a−b)[(a−b)^2+3ab]
a^3−b^3=4×(4^2+3×45)=4×(16+135)=4×151=604
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hope this helps
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