Question

If a - b = 4 and a + b = 6; find :
(1) a² +b² (ii) ab​

Answer 1

Answer:

(i) $a^{2} +b^{2} =26  (ii) ab=5</p><p><strong>Step-by-step explanation:</strong></p><p>a-b=4-----(1)</p><p>a+b=6----(2)</p><p>elemination method</p><p>2a=10</p><p>a=5</p><p>put value of a in (1)</p><p>5-b=4</p><p>-b=-1</p><p>b=1</p><p>(i) [tex]a^{2} +b^{2} =5^{2} + 1^{2}$

[tex]a^{2} +b^{2} =25+1=26

(ii)ab=5(1)=5

Answer 2

Answer:

(1) 26

(2)5

Explanation:

a+b=6

a-b = 4

________(add)

2a = 10

________

a=5

a+b=6

5+b=6

b=1

(1)a^2+b^2= 5^2 + 1^2

=25+1=26

(2)ab=5×1 = 5