Question

if a - b = 4 and a + b = 6. find
(I)
${a}^{2} + {b}^{2}$
(ll) ab

using suitable identity


no scam otherwise the answer will be report.​

Answer 1

Answer:

a-b=4______(1)

a+b=6______(2)

from 1 and 2 we get

2a=10

a=5

put a=5 in 2 we get

b=1

so ab=5×1=5

and a^2+b&2=(5)^2+(1)^2=25+1=26

Step-by-step explanation:

PLSPLSPLS MARK BRAINLIEST

Answer 2

Step-by-step explanation:

There is no need to follow any complex formula. It is quite simple question and quite simple solution.

Here,

a + b = 6 ————-(i)

and

a - b =4 ———— (ii)

Adding equation i and ii, we get

a + b = 6

a - b = 4

2a =2

or a = 2/2 = 1

Put this value in equation i and ii, we get the value of b,

in equation i,

a + b = 6

1 + b = 6

or b = 6 - 1 = 5

in equation ii

a - b = 4

1 - b = 4

or - b = 4 + 1 = 5

Hence, a square + b square = a sq + b sq = 1 sq + 5 sq

= 1 + 25 = 26

Note:- Quora is not taking super script command that’s why I wrote square or sq.