Question

If a + b = 4 and ab = -12, find (1) a - b (ii) a^2 - b^2.
please answer my question​

Answer 1

$a + b = 4 \\ {(a + b)}^{2} = {4}^{2} \\ {a}^{2} + 2ab + {b}^{2} = 16 \\ {a}^{2} - 2ab + {b}^{2} + 4ab = 16 \\ {(a - b)}^{2} = - 4ab + 16 \\ {(a - b)}^{2} =( - 4 \times - 12 )+ 16 \\ {(a - b)}^{2} = 48 + 16 \\ {(a - b)}^{2} = 64 \\ a - b = 8$
${a}^{2} - {b}^{2} \\ (a + b)(a - b) \\ (4)(8) \\ 32$