If a +b =4 and ab = -12, find (a²+b²).
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0
Answer:
the value of a2 +b2 =26
Step-by-step explanation:
Given
a-b = 4
=> a = 4+b ----(1)
and
a+b=6 ----(2)
Substitute (1) in equation (2), we get
=> 4+b+b=6
=> 4+2b=6
=> 2b=6-4
=> 2b=2
\implies b = \frac{2}{2}⟹b= 2^2
\implies b = 1⟹b=1
Now ,
put b = 1 in equation (1), we get
a=4+1
=> a = 5
\begin{gathered}Value\: of\: a^{2}+b^{2}\\=5^{2}+1^{2}\\=25+1\\=26\end{gathered}
Value Of A ^2 +b ^2
=5 ^2 +1 ^2
=25+1
=26
Therefore,
The\: value\:of \:a^{2}+b^{2}=26The value of
a ^2+b ^2 =26
Answered by
1
Step-by-step explanation:
JO BHI HAI TU MAI KRISHNA HU AUR FAKE ACCOUNT SAI MAT CHLA.
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