If a+b=4 and ab= –12 , find i) a-b & ii) a²-b²
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a+b = 3 and ab= -12
then, b= 3-a
and a(3-a) = -12
or, 3a-a^2 = -12
or, a^2 -3a -12 = 0
or, a= 3+√9+48 / 2
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