if a-b=4 and ab=2 find a cube-b cube
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a^3 - b^3
= (a-b) (a^2 + b^2 + ab)
= (a-b) (a^2 + b^2 - 2ab + 3ab)
= (a-b) { (a-b)^2 + 3ab}
= 4 (4^2 + 3×2)
= 4 (16 + 6)
= 4×22
= 88
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