Math, asked by aisyah6716, 10 months ago

If a-b=4 and ab=21 fi d the value of a³-b³

Answers

Answered by kesavan6174
2

Answer:

a^3-b^3=(a-b)^3+3ab(a-b)

=4^3 +3*21(4)

=64+252

=316

Answered by Anonymous
2

\Huge{\purple{\underline{\textsf{Answer}}}}

\large{\red{\underline{\tt{Given:}}}}

a - b = 4

ab = 21

\large{\red{\underline{\tt{To find:}}}}

The value of a³-b³.

Step-by-step explanation:

\large{\red{\underline{\tt{Solution:}}}}

 \implies\rm (a-b)^3</p><p>

 \implies\rm a^3-3a^2b+3ab^2-b^3

 \implies\rm a^3-3ab(a-b)-b^3

 \implies\rm 4^3=a^3-b^3-3(21)(4)

 \implies\rm 64+252=a^3-b^3

 \implies\rm a^3-b^3=<strong>316</strong>

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