If a-b=4 and ab=21 find value of a3-b3
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Answered by
19
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YOUR ANS IS HERE.... ⤵
Given that
a - b = 4
ab = 21
We know that..
a³- b³ = (a-b)³ + 3ab(a-b)
Substitute the given values in the formula
a³ - b³ = (4)³ + 3x21 (4)
a³ - b³ = 64 + 252
a³ - b³ = 316
Therefore a³ - b³ = 316
HOPE THIS HELPS U✌✌✋
YOUR ANS IS HERE.... ⤵
Given that
a - b = 4
ab = 21
We know that..
a³- b³ = (a-b)³ + 3ab(a-b)
Substitute the given values in the formula
a³ - b³ = (4)³ + 3x21 (4)
a³ - b³ = 64 + 252
a³ - b³ = 316
Therefore a³ - b³ = 316
HOPE THIS HELPS U✌✌✋
Answered by
4
a-b=4
ab=21
a3-b3=?
(a-b)3 = a3-b3-3ab(a-b)
(4)3 = a3-b3-3(21)(4)
64 = a3-b3-252
a3-b3= -252+64= -188
Ans.=a3-b3= -188
ab=21
a3-b3=?
(a-b)3 = a3-b3-3ab(a-b)
(4)3 = a3-b3-3(21)(4)
64 = a3-b3-252
a3-b3= -252+64= -188
Ans.=a3-b3= -188
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