if (a+b) =4 and ab =3,find the value of a^3+b^3
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a+b=4
a = 4 - b -----(1)
ab = 3
from eq (1)
( 4 - b )b = 3
4b - b^2 = 3
-b^2 + 4b - 3 = 0
b^2 - 4b + 3 = 0
b^2 - b - 3b + 3 = 0
b ( b - 1 ) -3 ( b - 1 ) = 0
( b - 3 ) ( b - 1 ) = 0
b - 3 = 0 b - 1 = 0
b = 3 b = 1
if b = 3 then a = 1
if b = 1 then a = 3
a^3 + b^3 = 1^3 + 3^3
= 1 + 27
= 28
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