Question

If a+b=4 find the value of a3+b3+12ab-64

Answer 1

Given that a+b=4 and to find a^3+b^3+12ab-64 value

                     

                (a + b)^3 = a^3 + b^3 + 3ab(a + b)

                  64= a^3+b^3+ 12ab

                   0= a^3+b^3+12ab-64

   the answer is 0

Please mark as brainliest if you think the answer helped