If A+ B = π/4
Prove that
( cot A -1) (Cot B -1) = 2.
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Solution
==>
We have ,
A+B = π/4
taking cot both sides .
cot(A+B ) = cotπ/4
We know that
cot (a+b) = cot a cot b -1 / cot a +cot b.
Cot A cot B -1/ cot A + cot B = 1
cot A + cot B = cot A cot B -1
cot A cot B - cotA - cot B = 1
Adding 1 both sides.
cotA cotB - cot A - cot B +1 = 2
cot A ( cot B -1 ) -1 ( cotB - 1) = 2
(cot B -1 ) ( cot A -1 ) = 2 .
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