If A=B=45 then prove that sin(A+B) =sinAcosB + cosAsinB
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Sin(A+B)=sin 90°=1
sinAcosB+cosAsinB=1/√2×1/√2+1/√2×1/√2=1/2+1/2=1
sinAcosB+cosAsinB=1/√2×1/√2+1/√2×1/√2=1/2+1/2=1
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