If A+B = 45° show that (1+tanA)(1+tanaB)= 2
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Step-by-step explanation:
We have A+B = 45° So we will pt tan on both sides.
It will be tan(A+B) = tan 45°
we know that tan 45° = 1
And on L. H. S. we will use the formula for tan(A+B) = [tan A +tan B]/[1 - (tanA) (tanB)]
then finally just simplify it.
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