Question

if A=B=45°, so proof that sin(A+B)=sinA cosB + cosA sinB​

Answer 1

Step-by-step explanation:

A=B=45°

sin(A+B)=sinA cosB + cosA sinB

sin(45+45)=sin45cos45+cos45sin45

sin90=(1/√2)(1/√2)+(1/√2)(1/√2)

1=1/2+1/2

1=1

LHS=RHS

Hence proved

Answer 2

Answer:

RHS=sin(A+B) =90°=1

LHS=sinAcosB+cosAsinB=1/√2*1/√2+1/√2*1/√2

=1/2+12

=1

Hence proved