Question

if A+B = 45° then (1+ tanA) (1+tanB) is equal to

Answer 1

A+B=45°

so, tan(A+B)= tan45

tanA+tanB/1- tanAtanB=1

tanA+ tanB= 1-tanAtanB

tanA +tanB+ tanAtanB=1

1+tanA +tanB+ tanAtanB=1+1     (adding 1 on both sides)

1(1+tanA) +tanB(1+tanA) =2

(1+tanA)(1+tanB)=2

Thus, (1+tanA)(1+tanB)=2

Answer 2

hope u can understand