If A+B=45° , then prove that (1+tanA) (1+tanB)=2
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Answered by
0
Answer:
tan (A+B) =tan45
tanA+tanB/1+tanAtanB=1
tanA+tanB=1+tanAtanB
Answered by
1
Step-by-step explanation:
Given A+B=45
{Take tan on both the sides }
tan(A+B) = tan45
tanA+tanB/1- tanA tanB = 1
tanA+tanB=1-tanA.tanB
tanA+tanB+tanA.tanB=1
adding "1" on both sides
1+ tanA+tanB+tanA.tanB=1+1
(1 + tanA)+tanB(1+tanA).=2
(1+tanA)(1+tanB)=2 Hence proved .
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