Math, asked by bansal78, 7 months ago

if A+B=45°prove that tanA+tanB+tanAtanB=1

Answers

Answered by bagkakali

2

Answer:

tan(A+B)=(tanA+tanB)/(1-tanA.tanB)

tan45=1=tanA+tanB/1-tanA.tanB

tanA+tanB=1-tanAtanB

tanA+tanB+tanAtanB=1 (proved)

Answered by lakshittyagi17

1

tan(A+B)=(tanA+tanB)/(1-tanA.tanB)

tan45=1=tanA+tanB/1-tanA.tanB

tanA+tanB=1-tanAtanB

tanA+tanB+tanAtanB=1

hence proved

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