if A+B=45°prove that tanA+tanB+tanAtanB=1
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Answered by
2
Answer:
tan(A+B)=(tanA+tanB)/(1-tanA.tanB)
tan45=1=tanA+tanB/1-tanA.tanB
tanA+tanB=1-tanAtanB
tanA+tanB+tanAtanB=1 (proved)
Answered by
1
tan(A+B)=(tanA+tanB)/(1-tanA.tanB)
tan45=1=tanA+tanB/1-tanA.tanB
tanA+tanB=1-tanAtanB
tanA+tanB+tanAtanB=1
hence proved
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