If a-b=4and ab=45 find a^3-b^3
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Answered by
2
hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝
GIVEN That:- a-b=4
ab=45
then
,
a³-b³
(a-b)(a²+ab+b²)
(a-b)(a²+b²+ab)
{(a-b){(a-b)²+2ab +ab)
(4){(4)²+2*45+44)
4*16+90+44
64+90+44
198
That's all
GIVEN That:- a-b=4
ab=45
then
,
a³-b³
(a-b)(a²+ab+b²)
(a-b)(a²+b²+ab)
{(a-b){(a-b)²+2ab +ab)
(4){(4)²+2*45+44)
4*16+90+44
64+90+44
198
That's all
PRITESHKUMAR:
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Answered by
16
(a-b)^2=a^2 + b^2 -2ab
16+90=a^2 + b^2
now
a^3-b^3 =( a-b )(a^2 + b^2 +ab)
= (4)(16+90+45)
= 604
16+90=a^2 + b^2
now
a^3-b^3 =( a-b )(a^2 + b^2 +ab)
= (4)(16+90+45)
= 604
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