If a : b = 5 : 2, find a + 3b : 3a + b?
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Now substitute for a in the algebraic expression:
(2a+3b)/(3a-2b)
A = 3b/2
(2(3b/2)+3b)/(3(3b/2)-2b
(6b/2 + 3b)/(9b/2–2b)
Multiply all terms by 2 to eliminate the fractions:
(6b+6b)/(9b-4b)
12b/5b
Divide out the B’s:
12/5
So (2a+3b)/(3a-2b) = 12/5
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