Question

if A:B=5:6& B: C=8:9, find A:B:C

Answer 1

here is ur answer....

Answer 2

A : B = 5 : 6 ; B : C = 8 : 9






As b is different in both the ratios. We have to make the value of B same in both the ratios. To make the value of B same in both, multiply by a number so the values of B become equal to the lowest common multiple ( LCM ) of both the values of B.



LCM of 6 and 8 = 24



Now,



A : B = ( 5 × 4 ) : ( 6 × 4 ) ; B : C = ( 8 × 3 ) : ( 9 × 3)


A : B = 20 : 24 ; B : C = 24 : 27



.
Now values of both Bs is same in both the ratios. We can easily calculate the value of A : C



Then, in the question,


$A : C = \dfrac{A }{C }$


Divide both A and C by B ,

$= > \dfrac{ \frac{A }{ B} }{ \frac{C }{B } }$

Hence,



$= > \dfrac{ \dfrac{20}{24} }{ \frac{27}{24} } \\ \\ \\ = > \frac{20}{27}$




But Question was to found A : B : C


B is already same. So It will be

20 : 24 : 27