Question

If a:b=5:6 and b:c =8:5 then find tje valie of (a+b+c)/(2a-b-c)

Answer 1

hope it helps you.............

Answer 2

Answer:

59

Step-by-step explanation:

Given a/b=5/6

Multiplying by 4 in both numerator and denominator.

a/b = (5×4)/(6×4) = 20/24

And b/c = 8/5

Multiplying by 3 in both numerator and denominator.

b/c = (8×3)/(5×3) = 24/15

So a:b:c = 20:24:15

Now let H.C.F. of a, b, c = x

So a = 20x, b = 24x, c = 15x

∴ (a+b+c)/(2a-b-c) = (20x+24x+15x)/(40x-24x-15x)

= 59x/x

= 59

So answer is 59.

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