Question

If a+b=5,a-b=1, find the value of 8ab(a^2+b^2).​

Answer 1

Answer:

624

Step-by-step explanation:

a+b= 5_______(1)

a-b= 1

a= 1+b________(2)

substitute (2) in (1)

1+b+b = 5

1+2b= 5

b= 4/2 = 2

so, a = 1+b = 1+2 = 3______from(2)

substitute the values of a and b in 8ab (a²+b²)

=> 8×3×2 ( 3²+2²)

= 48(9+4) = 48 × 13 = 624

Answer 2

Answer:

the answer is 624

Step-by-step explanation:

a+b=5

a-b=1

2a=6

a=3

b=2

8ab(a2+b2)

8×3×2(9+4)

624