If a+b=5,a-b=1, find the value of 8ab(a^2+b^2).
Answers
Answered by
2
Answer:
624
Step-by-step explanation:
a+b= 5_______(1)
a-b= 1
a= 1+b________(2)
substitute (2) in (1)
1+b+b = 5
1+2b= 5
b= 4/2 = 2
so, a = 1+b = 1+2 = 3______from(2)
substitute the values of a and b in 8ab (a²+b²)
=> 8×3×2 ( 3²+2²)
= 48(9+4) = 48 × 13 = 624
Answered by
0
Answer:
the answer is 624
Step-by-step explanation:
a+b=5
a-b=1
2a=6
a=3
b=2
8ab(a2+b2)
8×3×2(9+4)
624
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