Question

if (a-b)=5,ab=36.Then the value of (a-b)^2​

Answer 1

Step-by-step explanation:

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Answer 2

$\huge\sf\pink{Hey\:User}$

$\large\mathbb\blue{ANSWER}$

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$(a-b)=5$

$ab=36$

$\huge\sf\pink{TO\:FIND}$

$a^2+b^2$

$\text{USING IDENTITY (a-b)^2}$

$\implies\sf\blue{(a-b)^2=a^2-2ab+b^2}$

Now,Put the values.

$\implies\sf\blue{(5)^2=a^2-2×36+b^2}$

$\implies\sf\blue{72-25=a^2+b^2}$

$\implies\sf\blue{a^2+b^2=47}$

$\implies\sf\blue{USEFUL\:IDENTITIES}$

$(a+b)^2=a^2+b^2+2ab$

$a^2-b^2=(a+b) (a-b)$

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