Math, asked by Kishansah4792, 1 year ago

If a+b=5 and a-b=2 then value of a^2-b^2 is

Answers

Answered by Anonymous
0

Answer:

(a+b)(a-b)=5*2

a^2-b^2=10

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Answered by kartik2507
0

Step-by-step explanation:

(a+b)(a-b) = a^2 - b^2

a + b = 5

a - b = 2

5 × 2 = 10

a^2 - b^2 = 10

a + b = 5

a - b = 2

adding

2a = 7

a = 7/2

a + b = 5

7/2 + b = 5

b = 5 - 7/2

b = (10 - 7)/2

b = 3/2

 {a}^{2}  =  { (\frac{7}{2} )}^{2}  =  \frac{49}{4}  \\  {b}^{2}  =  {( \frac{3}{2}) }^{2}  =  \frac{9}{4}  \\  {a}^{2}  -  {b}^{2}  =  \frac{49}{4}  -  \frac{9}{4}  =  \frac{49 - 9}{4}  =  \frac{40}{4}  = 10

hope you get your answer

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