Math, asked by ishachavan501, 7 months ago

if (a+b) = 5 and (a-b) = 3, then a^2-b^2= ?

Answers

Answered by harshitha926594
4

Answer:

a + b = 5 \\ a - b = 3 \\  -  -  -  -  -  \\ 2a = 8 \\ a =  \frac{8}{2}  \\  \boxed{a =  \underline{ \underline{4}}} \\  \\ a - b = 3 \\ 4 - b = 3 \\ 4 - 3 = b \\  \boxed{ \underline{ \underline{1}} = b} \\  \\  {a}^{2}  -  {b}^{2}  \\  =  {4}^{2}  -  {1}^{2}  \\  = 16 - 1 \\   \large{ \boxed{=  \underline{ \underline{15}}}}

Answered by pulakmath007
1

SOLUTION

GIVEN

a + b = 5 & a - b = 3

TO DETERMINE

The value of a² - b²

FORMULA TO BE IMPLEMENTED

We are aware of the identity that

 \sf{ {a}^{2} -  {b}^{2}  = (a + b)(a - b) }

EVALUATION

Here it is given that a + b = 5 & a - b = 3

Now

 \sf{ {a}^{2} -  {b}^{2} }

 \sf{   = (a + b)(a - b) }

 \sf{  = 5 \times 3 }

 \sf{  = 15 }

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