if a+b=√5 and a-b=√3, then find
8ab(a^2 + b^2)
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Given :
- a + b = √5
- a - b = √3
To find :
- 8ab (a² + b²)
Solution :
Take both equation square
a² + b² = 5
a² - b² = 3
2a² = 8
a² = 8/2
a² = 4
a = √4
Putting a = √4
a + b √5
√4 + b = √5
taking square
4 + b² = 5
b² = 5 - 4
b² = 1
b = 1
Finding 8ab (a² + b²)
8 × √4 × 1 (√4² + 1)
16 + 4 + 1
21
Answer is 21.
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