Question

if a-b=5 and ab=4 find the value of a2+b2

Answer 1

Given:

a₋b = 5 and ab = 4

To find:

The value of a²+b²

Solution:

As we know from algebraic identities (a - b)² = a² + b² -2ab

⇒ (a - b)²+ 2ab = a² + b² + 2ab - 2ab = a² + b²  

⇒ a² + b² = (a - b)²+ 2ab   We will use this to solve given problem

From given data  

a ₋ b = 5 and ab = 4  

⇒  a² + b² = (a - b)²+ 2ab  

= (5)² + 2(4) = 25 + 8 = 33

The value of a²+b² = 33

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Answer 2

Given:

$a-b = 5$ and $ab = 4$

To find:

The value of $a^{2} +b^{2}$

Solution:

As we know from algebraic identities $(a - b)^{2} = a^{2} + b^{2} -2ab$

⇒ $(a - b)^{2} + 2ab = a^{2} + b^{2} + 2ab - 2ab = a^{2} + b^{2}$

⇒ $a^{2} + b^{2} = (a - b)^{2} + 2ab$  

From given data  

$a - b = 5$ and $ab = 4$

⇒  $a^{2} + b^{2} = (a - b)^{2} + 2ab$

= $(5)^{2} + 2(4) = 25 + 8 = 33$

The value of $a^{2} +b^{2} = 33$

How does simplification work?

• Finding the answer to a complex calculation through simplicity is what the exam's simplification topic entails. As a result, you may learn how to do better on exams like SBI Clerk, RBI Assistant, SBI PO, IBPS Clerk, IBPS PO, SSC SGL, and SSC CHSL in this post.

• Right now, we'll talk about the many types of simplification.

• You all must be familiar with both types of simplification questions since they will be asked in two different ways. The first is "Finding the Missing Number."

• "The relationship between the numbers and simplify the numbers using the rules of simplification" is the second category of simplification question.

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