Question

if (a+b)=5 and (ab)=6 find the value of (a-b)^2

Answer 1

Answer:

a - b = 1

Step-by-step explanation:

(a+b)^2 = (a-b)^2 + 4ab

(5)^2 = (a-b)^2 + 4(6)

25 - 24  = (a-b)^2

therefor (a-b)= 1

Answer 2

We have,

(a+b) = 5 and (ab ) =6

So, (a+b)^2= a^2 + b^2 + 2ab

=> 25 = a^2 + b^2 + 12

=> 25 - 12 = a^2 + b^2

=> a^2 + b^2 = 13......(1)

Thus, (a-b)^2 = a^2 + b^2 - 2ab
= 13 - 12 ( using 1 )
= 1. Ans