Question

if a+b=5 and ab=6 then find the value of a3b3

Answer 1

Answer:

216

Step-by-step explanation:

a=2

b=3

a³=2³=8

b³=3³=27

a³b³=27×8=216

Answer 2

$\huge\mathcal\colorbox{yellow}{{\color{blue}{AnSwEr~↓~↓~}}}$

$\huge{\boxed{35}}$

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

$a^{3}+b^{3}$

[/tex]{=(a+b)^{3}-3ab(a+b)a3+b3=(a+b)3−3ab(a+b)}[/tex]

${=53−3×6×5}$

${=125−90}$

${=35}$