Question

if (a+b)=5 and ab=6,then find the value of I) a^2+b^2,ii)a-b, III) a^2-b^2,iv)a and b?

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Answer 1

Step-by-step explanation:

i) 13

ii) 1

iii) 5

IV) 3 and 2 respectively

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Answer 2

(a+b)  ^2 =a  ^2 +b  ^2 +2ab

=>a^2 +b^2 =(a+b)^2 −2ab

Given, a+b=5 and ab=6

So, a ^2 +b^ 2 =(a+b) ^2  −2ab=5^2−2×6=25−12=13

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